представьте в виде многочлена 3y3 5 2

Ответ от Вячеслав ***[гуру]
1. а) (c - 9) (c - 3) - 6c (3c - 2)
(c - 9) * (c - 3) - 6c * (3c - 2) = c^2 - 3c - 9c + 27 - 18c^2 + 12c = 18c^2 - c^2 + 12c - 9c - 3c + 27 = 17c^2 + 27.
б) 4a (a - 5) - (a - 10)^2
4a * (a - 5) - (a - 10)^2 = 4a^2 - 20a - a^2 - 2 * a * (-10) - 10^2 = 4a^2 - 20a - a^2 + 20a - 100 = 4a^2 - a^2 + 20a - 20a - 100 = 3a^2 - 100.
в) (b + 2)^2 - 12b
(b + 2)^2 - 12b = b^2 + 2 * b * 2 + 2^2 - 12b = b^2 + 4b + 4 - 12b = b^2 - 8b + 4.
2. а) 7 x^3 - 28x
7 * x^3 - 28x = 7 * x * x * x - 28 * x.
б) 5a^2 - 10ab + 5b^2
5 * a^2 - 10ab + 5 * b^2 = 5 * a * a - 10 * a * b + 5 * b * b.
в) x^3 - 8
x^3 - 8 = x * x * x - 8.
3. (x^2 - 2x)^2 - (x - 2) (x + 2) (x^2 - 4) - 4x (7x - x^2)
(x^2 - 2x)^2 - (x - 2) * (x + 2) * (x^2 - 4) - 4x * (7x - x^2) = (x^2)^2 - 2 * x^2 * (- 2x ) - 2x^2 - x^4 + 16 - 28x^2 + 4x^3 = x^4 + 4x^3 - 2x^2 - x^4 + 16 - 28x^2 + 4x^3 = x^4 - x^4 + 4x^3 + 4x^3 - 28x^2 - 2x^2 + 16 = 8x^3 - 26x^2 + 16.
4. а) m^2 - (m + n)^2
m^2 - (m + n)^2 = m^2 - m^2 - 2 * m * n + n^2 = m * m - m * m - 2 * m * n + n * n.
б) x^3 - y^3 - 5x (x^2 + xy + y^2)
x^3 - y^3 - 5x * (x^2 + xy + y^2) = x^3 - y^3 - 5x^3 - 5x^2y - 5xy^2 = x * x * x - y * y * y - 5 * x * x * x - 5 * x * x * y - 5 * x * y * y.