tga ctga sin 2a

Ответ от Eugene Greek[гуру]
tg a/(tg a+1/tg a)=sin^2 a
tg a/(tg^2 a+1)/tg a=sin^2 a
tg a*tg a/(tg ^2 a+1)=sin^2 a
tg^2 a/(1/cos^2 a)=sin^2 a
sin^2 a/cos^2 a*cos^2 a=sin^2 a
sin^2 a=sin^2 a
Eugene Greek
Просветленный
(24273)
tg a+1/tg a=(tg^2 a+1)/tg^2 a